codek

learning, data mining, pattern recognition, image analysis and bioinformatics.The performance of K-means depends on the initial position of the cluster center, and it cannot ensure convergence to the optimal solution and is sensitive to outliers. You can use some front-end methods, first calculate the initial cluster center, or each time with a different initial cluster center to run the algorithm multiple times, and then determine the merit.Although the two-K-means clustering algorithm improve

-profile get defaultThe results are shown below, with the smallest erasure pool typeDirectory=/usr/lib/ceph/erasure-codek=2M=1Plugin=jerasureTechnique=reed_sol_van2. Add profileIt is important to select the appropriate profile when creating a pool, since pool creation cannot be modified, and if the profile of the two pool is different, all objects are moved from the old pool to the new pool when a new pool is created.The most important parameters of p

replicated min_size 1 max_size 10 step take metadata step chooseleaf firstn 0 type osd step emit}7. Create a pool(1) Create an ssd pool with the type of replicated command prototype: ceph osd pool create {pool-name} {pg-num} [{pgp-num}] [replicated] [crush-ruleset-name] actual command: ceph osd pool create ssd 128 128 repicated ssd(2) create a sata pool and the type is erasure command prototype: ceph osd pool create {pool-name} {pg-num} {pgp-num} erasure [erasure-code-profile] [crush-ruleset-na

When you get from HashMap, what are you actually doing?1 /**2 * Returns the value to which the specified key is mapped,3 * or {@codeNULL} If this maps contains no mapping for the key.4 *5 * 6 * {@codek} to a value {@codeV} such that {@code(key==null? K==null:7 * Key.equals (k))}, then this method returns {@codev}; otherwise8 * It returns {@codenull}. (There can is at the most one such mapping.)9 *Ten * @codenull} does not One * indicat

*/ - Wuyi for(i=0; i) the { - intnum=0; Wu floats0=0.0; - floats1=0.0; About //cout $ for(j=0; j) - { - if(mindis[j]==i) - { Anum++; + //cout thes0+=xy[2*j]; -s1+=xy[2*j+1]; $ } the } the if(num) the { thecxy[2*i]=s0/num; -cxy[2*i+1]=s1/num; in } the //cout the

mapped,3 * or {@codeNULL} If this maps contains no mapping for the key.4 *5 * 6 * {@codek} to a value {@codeV} such that {@code(key==null? K==null:7 * Key.equals (k))}, then this method returns {@codev}; otherwise8 * It returns {@codenull}. (There can is at the most one such mapping.)9 *Ten * @codenull} does not One * indicate that the map contains No. mapping for the key; it ' s also A * Possible that the map explicitly maps the key

} If this maps contains no mapping for the key. * * @codek} to a value {@codeV} such that {@code(key==null k==null: * key.equals (k))}, then this method returns {@codev}; otherwise * it returns {@codenull}. (There can is at the most one such mapping.) * * @codenull} does not @codenull}. * The {@link#containsKey ContainsKey} operation is used to * distinguish these and cases. * * @see#put (Object, Object)*/ PublicV get (Object key) {if(Key

length of a codeword N and n + 2 is as follows: C (n + 2, 1) = (C (n, last) + 1) 8. One dollar code Encode a non-negative integer N with N numbers 1 and 0 No need to store the code table It can be represented by the Huffman tree. Code length increases too fast: N = 100, code length 101 9. Columbus code Divides the source symbol into several groups, each group has a corresponding number Small allocation code word is short, and the number is very long. The same gr

Find the kth largest element in an unsorted array. Note that it was the kth largest element in the sorted order and not the kth distinct element.For example,Given [3,2,1,5,6,4] and k = 2, return 5.Note:You may assume k are always valid, 1≤k≤array ' s length.Credits:Special thanks to @mithmatt for adding this problem and creating all test cases.Runtime:12ms1 classSolution {2 Public:3 intFindkthlargest (vectorint> Nums,intk) {4 intn =nums.size ();5 if(n = =0|| K > N)return 0;6

),//t is the copy of the array itself this is Len = T.length >>> 0,//array length k = 0,//array subscript variable accumulator//the variable that holds the result if (typeof fun! = ' function ') throw new TypeError () if (len = = 0 arguments.length = 1) throw new TypeError () 21//Take initial value 22 if (arguments.length >= 2) accumulator = arguments[1]//If the parameter length is greater than 2, the second parameter is the initial value of4 if (k in t) {accumulator = t[k++]//Otherwise th